Math, asked by AadithyaaBabiloo, 1 year ago

a square+ac+bc-b square (factorise)

Answers

Answered by SmãrtyMohït
13
✌✌Here is your answer ✌ ✌

\huge\boxed{\red{\bold{Solution}}}

 = a {}^{2} + ac + bc - b {}^{2} \\ = a {}^{2} - b {}^{2} + ac + bc \\ = ( a + b)(a - b) + c(a + b) \\ =(a+b)(a-b+c)

Note:-
a {}^{2} - b {}^{2} = (a + b)(a - b)
it is a formula .
\huge\underline{\purple{\bold{Thanks}}}
I hope it helps you

Swarup1998: Great thanks! (:
Answered by Ashishkumar098
4
Ello !!

Here's your answer

_______________________

Factories of : a^2 + ac + bc - b^2



= > a^2 + ac + bc - b^2

= > ( a )^2 - ( b )^2 + ac + bc

= > ( a + b ) ( a - b ) + c ( a + b )

[ • Taking common ' c ' ]

[ • We know , ( a )^2 - ( b )^2 = ( a + b ) ( a - b ) ]

= > ( a + b ) ( a - b + c )

[ • Now taking common ' ( a + b ) ' ]

______________________

Hope it helps you!

★ Devil king
Similar questions