Question

a square and a equilateral triangle have the equal perimeter. if the diagonal of the square is 12√2 cm2 find the area of the triangle. ​

Answer 1

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Diagonal of square = √2a

√2a = 12√2

a = 12cm

perimeter of square = 4a = 4*12 = 48cm

perimeter of equilateral ∆ = 48cm = 3s

s(side of ∆) = 16cm

Area of eq∆ = √3/4(a)² = √3*16*16/4 = 64√3 cm² (Ans)

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Answer 2

Step-by-step explanation:

diagonal of squareequals to root 2 * side so side of square is equals to 12 CM

now perimeter of square =perimeter of equilateral triangle

perimeter of square=48 xm^2

now 3a=48

a=48/3

area =root3/ a^2

root3 /4*48/3*48/3

By solving it we get area =64 root 3