Question

a square and a rectangle have same perimeter. if the side of a squre is 48cm and length of a rectangle is 70cm then whose area is more and by how much????
Helpp​

Answer 1

Answer:

side of a square =48 cm

perimeter of the square =48×4 cm=192 cm

so perimeter of the rectangle =192 cm

length og the rectangle =70cm

breadth of the rectangle={(perimeter/2)- length}

={(192/2)-70} cm

=(96-70) cm

=26 cm

then area of the rectangle

=length×breadth

=70×26 sq cm

=1820 sq cm

and area of the square

=side^2

=48×48 sq cm

=2304sq cm

so area of the square is more

(2304-1820)sq cm

=484 sq cm

area of the square is 484 sq cm greater than rectangle

Answer 2

Answer :-

Given :-

• Perimeter of square = Perimeter of rectangle
• Side of square = 48 cm
• Length of rectangle = 70 cm

To Find :-

• Whose area is more and by how much

Solution :-

→ Perimeter of square = 4 × side

→ P = 4 × 48

→ P = 192 cm

→ Perimeter of rectangle = 2 ( Length + Breadth )

→ P = 2 ( 70 + Breadth )

Given that,

Perimeter of square = Perimeter of rectangle

→ 192 = 2 ( 70 + B )

→ 70 + B = 192 / 2

→ 70 + B = 96

→ B = 96 - 70

→ B = 26

Calculating area of square :-

→ Area of square = side × side

→ Area of square = 48 × 48

→ Area of square = 2304

→ Area of square = 2304 cm²

Calculating area of rectangle :-

→ Area of rectangle = Length × Breadth

→ Area of rectangle = 70 × 26

→ Area of rectangle = 1820

→ Area of rectangle = 1820 cm²

Hence, area of square is greater than area of rectangle

→ Area of square - Area of rectangle

→ 2304 - 1820

→ 484

Area of square is greater than area of rectangle by 484 cm²