A square and a rectangle have the same perimeter. If the area of the square is 192 cm2 and the length of the rectangle is 4 more than its breadth, find the perimeter, area and the dimensions of the rectangle.
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Step-by-step explanation:
Let the length of the rectangle =l cm and breadth =b cm.
Area of the rectangle =l×b=192cm
2
....(1)
Perimeter of the rectangle =2(l+b)=56 cm
⇒l+b=28 or l=28−b ....(2)
Putting the value of l in equation (1), we get
(28−b)×b=192
28b−b
2
=192
b
2
−28b+192=0
(b−16)(b−12)=0
=>b=16 or 12 cm
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