A square and rectangle has same perimeter. The perimeter of square is 44cm.the side of square is 5 times the length of rectangle.find the sum of area of square and rectangle?
Answers
Answer: 208.12
Step-by-step explanation:
Perimeter of square = 4S = 44
Therefore, S = 11
S = 5l, l= S/5
Perimeter of Rectangle = 2(l+b)
A/Q-:
Perimeter of square = Perimeter of Rectangle
4S =2(l+b)
44 = 2*11/5 + 2b
b =44 - 22/5
b = 39.6cm,l= 2.2cm
sum of area = area of square + area of rectangle
= 121 +87.12
=208.12
Answer:
A square and rectangle has same perimeter. The perimeter of square is 44cm.the side of square is 5 times the length of rectangle.find the sum of area of square and rectangle?
Answer: 164.5 cm
Step-by-step explanation:
Solution:
Suppose side of square = a and length & breadth of rectangle = l, b respectively
according to question
perimeter of square = 44 cm
⇒ 4a = 44
⇒ a = 44 / 4
⇒ a = 11 cm
area of square = a * a = 11 * 11 = 121
again according to question
side of square is 5 time the length of rectangle.
Hence, side of square = 5 x length of rectangle
⇒ a = 5 l
⇒ 11 = 5 l
⇒ l = 11 / 5
again perimeter of rectangle = 2 ( l + b)
a.c. question
square and rectangle has same perimeter.
2 ( l + b ) = 44
⇒ l + b = 22
⇒ 11 / 5 + b = 22
⇒ b = 22 - 11 / 5
⇒ b = 99 / 5
There area of rectangle = l x b = 11 / 5 * 99 / 5
= 1089 / 25
= 43. 56
sum of area of square and rectangle = 121 + 43.5 = 164.5 cm
Therefore sum of area of square and rectangle will be 164.5 cm