Question

A square and rectangle have the same perimeter. If the side of square is 16m and a square and rectangle have the same perimeter if the side of the square is 16 and the length of the rectangle is 18 the breadth of the rectangle is what ​

Answer 1

Answer:

first step

find the perimeter of square which is 4s

side given of the square=16

so16*4=64

as the perimeter of square and rectangle are same

so the perimeter of rectangle is 64

64=2(l+b)

64/2=l+18

32=l+18

l=32-18

l=14

so the length of the rectangle is 14

Answer 2

$\large{\boxed{\underline{\underline{\bf{APPROPRIATE \:QUESTION:-}}}}}$

A square and rectangle have the same perimeter. If the side of square is 16m and the length of the rectangle is 18m. What is the breadth of the rectangle ?

$\huge{\boxed{\underline{\underline{\bf{GIVEN:-}}}}}$

• The perimeter of square and rectangle are equal.
• Side of square is 16 m
• Length of the rectangle is 18 m

$\huge{\boxed{\underline{\underline{\bf{TO\:FIND:-}}}}}$

Find the breadth of the rectangle = ?

$\large{\boxed{\underline{\underline{\bf{FORMULA\:USED:-}}}}}$

$\large{\boxed{\bf{\blue{Perimeter \:of\:square = 4 \times side}}}}$

$\large{\boxed{\bf{\blue{Perimeter \:of\:rectangle = 2(l + b)}}}}$

$\huge{\boxed{\underline{\underline{\bf{SOLUTION:-}}}}}$

∴ We have given that, the perimeter of square and rectangle are equal

According to given conditions :-

∴ Perimeter of square = Perimeter of rectangle

$\implies$$\rm{4 \times side = 2(l + b)}$

Putting the given values in the formula, we get

$\implies$$\rm{4 \times 16 = 2(18 + b)}$

$\implies$$\rm{64 = 36 + 2b}$

$\implies$$\rm{2b = 64 - 36}$

$\implies$$\rm{2b = 28}$

$\implies$$\rm{b = \cancel\dfrac{28}{2}}$

$\implies$$\large\rm\blue{b = 14\: m}$

Thus, the breadth of the rectangle is 14 m

$\huge{\boxed{\underline{\underline{\bf{VERIFICATION:-}}}}}$

Put the value of 'l' and 'b' in the formula

$\implies$$\bf{4 \times 16 = 2(18 + 14)}$

$\implies$$\bf{4 \times 16 = 2 \times 32}$

$\implies$$\large\bf\blue{64 = 64}$

$\implies$$\rm{[L.H.S. = R.H.S.]}$

$\large{\underline{\underline{\bf{\blue{VERIFIED...}}}}}$