Question

A square and rectangular field with measurements as given in the 80 m and 100m have the same perimeter? Which field is the larger area​

Answer 1

Answer:

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Step-by-step explanation:

Let the side of square field be a=80 m

0 mLet the length of the rectangular field be l=80 m and breadth be b m.

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m 2

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m 2

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m 2 Area of rectangle=80×40=3200m

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m 2 Area of rectangle=80×40=3200m 2

0 mLet the length of the rectangular field be l=80 m and breadth be b m.According to the question perimeter of square = Perimeter of rectangle4×a=2(l+b)⇒4×60=2(80+b)⇒240=160+2b⇒2b=80⇒b=40Area of square =60×60=3600m 2 Area of rectangle=80×40=3200m 2

Answer 2

Supposition:-

• length of square = a = 80m.
• length of rectangle = l = 100m.
• breadth of rectangle = b m.

According to the question

$\underline{\boxed{\sf \ perimeter \ of \ square = Perimeter \ of \ rectangle}}$

$\implies$ $\sf{\:4×a=2(l+b)}$

$\implies$ $\sf{\:4×80=2(100+b)}$

$\implies$ $\sf{\:320=200+2b}$

$\implies$ $\sf{\:2b=120}$

$\implies$ $\sf{\:b=60m}$

$\implies$ $\sf{\:Area \ of \ square =80×80=6400m²}$

$\implies$ $\sf{\:Area \ of \ rectangle=100×60=6000m²}$

$\implies$ ${\boxed{\sf \ Area \ of \ square > area \ of \ rectangle}}$