a square +b square =7ab,prove that,2log (a+b)/3=log a +log b
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a^2+b^2=7ab
a^2+b^2+2ab=9ab
(a+b)^2 =9ab
(a+b/3)^2 =ab
log on both sides
log (a+b/3)^2 =log ab
,2log (a+b)/3=log a +log b
log (a^m) = m log a
log(ab) = loga+logb
a^2+b^2+2ab=9ab
(a+b)^2 =9ab
(a+b/3)^2 =ab
log on both sides
log (a+b/3)^2 =log ab
,2log (a+b)/3=log a +log b
log (a^m) = m log a
log(ab) = loga+logb
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