Question

a square b square plus b square plus. a square plus 1

Answer 1

a²b²+b²+a²+1

b²(a²+1)+1(a²+1)

(b²+1)(a²+1)

b=√-1 or a=√-1

Answer 2

Caution: There's not enough details given to understand the question.
Answer 1:
((ab)^2)+(b^2)+(a^2)+1
Answer 2:
$\sqrt{a}\sqrt{b}+\sqrt{b}+\sqrt{a}+1$

Alt Answer:
$a^{2}*b^{2}+b^{2} =a^{2}+1\\ \frac{ab^{2}+b^{2}}{b^{2}}=\frac{ a^{2}+1 }{b^{2}}\\ a^2+1=\frac{ a^{2}+1 }{b^{2}}$
Which can mean b is equal to one, and a can be eqaul to something.
But I could be wrong all along, because I don't know, due to the lack of  math formatting.

Step-by-step explanation:

Either you are talking about having to use code for the period or that there's no period there in the first place.

(this answer is not great.)