Question

A square board side 10 cm, standing
vertically is tilted to the left so that
the bottom – right corner is raised
6 cm from the ground. By what
distance is the top-left corner
lowered from its original position?

Answer 1

Answer:

2 cm.

Step-by-step explanation:

let the coordinate of the square (before rotation ) be

A(0,0) , B(10,0) , C(10,10) , D(0,10)

after Rotation

the coordinates of A will be the same

the coordinates of B will be B'(8,6)

the coordinates of D will be D'(6,8)

therefore

D' is lowered by a distance = 10 - 8 = 2 cm.