A square brass plate of side 1m and thickness 0.005m is subjected a forces f on its smaller opposite edges causing a displacement 0.2cm if the shear modulus is 0.4×10^11 value of force f?
Answers
Answered by
4
Hey mate,
● Answer-
F = 1.6×10^10 N
● Explaination-
# Given-
A = 1 m^2
h = 0.005 m
x = 0.002 m
η = 0.4×10^11
# Solution-
Shearing modulus is calculated by -
Shearing modulus = Shearing stress / shearing stress
η = (F/A) / (x/h)
F = η × A × x / h
F = 0.4×10^11 × 1 × 0.002 / 0.005
F = 1.6×10^10 N
Therefore, force of 1.6×10^10 N is used for shearing.
Hope it helps...
● Answer-
F = 1.6×10^10 N
● Explaination-
# Given-
A = 1 m^2
h = 0.005 m
x = 0.002 m
η = 0.4×10^11
# Solution-
Shearing modulus is calculated by -
Shearing modulus = Shearing stress / shearing stress
η = (F/A) / (x/h)
F = η × A × x / h
F = 0.4×10^11 × 1 × 0.002 / 0.005
F = 1.6×10^10 N
Therefore, force of 1.6×10^10 N is used for shearing.
Hope it helps...
Answered by
0
Answer:
4×10^4 is the correct answer
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