a square by b + c equal to b square by C + equal to C square by a + b equal to 1 then prove that 1 by 1 + 1 + 1 by 1 + b + 1 by 1 + 3 equal to 1
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b+c=b
so c=-b
c^2=(a+b)^2
hence (1+1+1)÷(1+1+b)÷(1+3)
=1
I think
so c=-b
c^2=(a+b)^2
hence (1+1+1)÷(1+1+b)÷(1+3)
=1
I think
Answered by
0
1 yes yes yes yes yes yes yes yes yes yes yes yes yes yes yes
srikanth00715:
hii
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