A square courtyard has an area of 59 m^2. If the area of the path uniform width surrounding outside the courtyard is 120 m^2. Find the width of the path. PLZ SOLVE THIS AS SOON AS POSSIBLE. AND DONT SPAME. CORRECT ANSWER WILL BE MARK AS BRAINLIEST
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Hello Mate!
Since we know that,
Area of outer Park - area of inner park = area of path.
Area of inner park = 59 m²
Area of outer park - 59 = 120 m²
Area of outer park = 120 + 59
Area of outer Park = 179 m² _(i)
In Inner Park,
Length = breadth .
Side² = 179 m²
Side = 13.4 m
In outer Park,
Length = breadth
Side² = 59 m²
Side = 7.7 m
Since we know that,
Outer length = inner length + 2( width )
Let the width be x,
13.4 m = 7.7 m + 2x
5.7 m = 2x
2.85 m = width.
Have great future ahead!
Since we know that,
Area of outer Park - area of inner park = area of path.
Area of inner park = 59 m²
Area of outer park - 59 = 120 m²
Area of outer park = 120 + 59
Area of outer Park = 179 m² _(i)
In Inner Park,
Length = breadth .
Side² = 179 m²
Side = 13.4 m
In outer Park,
Length = breadth
Side² = 59 m²
Side = 7.7 m
Since we know that,
Outer length = inner length + 2( width )
Let the width be x,
13.4 m = 7.7 m + 2x
5.7 m = 2x
2.85 m = width.
Have great future ahead!
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