Question

A square divided in to four equal triangles by drawing its diagonals .Area of one triangle is 9 .what is the side of square?

Answer 1

Answer:

Area of the square = Area of four triangles of the square

\begin{gathered} {a }^{2} = 4 \times 9 \\ a \: = \sqrt{36} \\ a = 6\end{gathered}

a

2

=4×9

a=

36

a=6

Answer 2

$A square \: divided \: in \: to \: four \: equal \: triangles \\ \: by \: drawing \: its \: diagonals \: \\ .Area \: of \: one \: triangle \: is \: 9 \: sq \: units. \\ \: \\ let \: side \: of \: square \: is \: x \: units \: \\ area \: of \: square \: = area \: of \: 4 \: triangles \\ {x}^{2} = 4 \times 9 \: sq \: units \\ x {}^{2} = 36 \: sq \: units \\ x = \sqrt{36 \: sq \: units} \\ x = 6 \: units$

Hence side of the square is 6 units.