Math, asked by kundankumarsharma041, 2 months ago

A square field is to be cultivated and fenced by fiber wire in three round. If side is
20m. Find -
7
). Cost of cultivation at the rate of Rs 50/m2
. Cost of fibered wire at rate of Rs 25/m.​

Answers

Answered by Lahariyenishetti
1

Step-by-step explanation:

fencing

perimeter of a square is 4a a is the side here side is 20 m so perimeter is 20×4 80m

it has to be fenced 3 rounds so 80×3

240m^2

cost of fibered wire will be 240×25 = 6000 rupees

cultivation we need to find area so area of a square field is s^2 side is 20 so 20^2= 20×20 400m^2

1 sq.m is rupees 50 so 400 will be 400×50= 20000 rupees

Answered by RvChaudharY50
0

Given :-

  • Side of square = 20 m.
  • Cost of cultivation = Rs.50/m².
  • Cost of fiber wire = Rs.25/m.

To Find :-

  • Total cost of cultivation and fiber wire. ?

Solution :-

we know that,

  • Perimeter of square = 4 * side .
  • Area of square = (side)² .

so,

→ Perimeter of square = 4 * 20 = 80 m.

then,

→ Length of fiber wire which was fenced three times = 80 * 3 = 240 m .

therefore,

→ Cost of fiber wire = Rate * Total length of wire = 25 * 240 = Rs.6000 . (Ans.)

also,

→ Area of square = Area of cultivation = (20)² = 400 m².

hence,

→ Cost of cultivation = Rate * Area of cultivation = 50 * 400 = Rs.20000 . (Ans.)

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