A square field is to be ploughed . Ramu gets it ploughed in 34560 rupees at the rate of 15 rupees per square metre. ( Do any four parts) (i) What is the area of the square plot (square metres)? (a) 2403 (b) 4302 (c) 48 (d) 2304 (ii) Find the length of side of square plot (metres) . (a) 84 (b) 48 (c) 40 (d) none of these (iii) Find the perimeter of the same plot (in metres)? (a) 920 (b) 192 (c) 240 (d) none of these (iv) If a person wants to plant 2704 medicinal plants in a square field and he planted them in form of rows. If each row contains as many plants as the number of rows, then find the number of rows. (a) 52 (b) 54 (c) 25 (d) none of these (v) How many plants are there in one row ? (Refer to the (iv) part) (a) 45 (b) 52 (c) 25 (d) none of these
Answers
Answer:
search-icon-header
Search for questions & chapters
search-icon-image
Class 7
>>Maths
>>Perimeter and Area
>>Perimeter and Area of a Circle
>>A path of 4 m width runs round a circula
Question
Bookmark
A path of 4 m width runs round a circular grassy plot whose circumference a 163
7
3
m Find
(i) the area of the path
(ii) the cost of gravelling the path at the rate of Rs.1.50 per square meter
(iii) the cost of turfing the plot at the rate of 45 paise per m
2
.
Hard
Solution
verified
Verified by Toppr
Circumference of plot=163
7
3
m
=
7
1144
m
⇒2πr=
7
1144
⇒r=
7×44
1144×7
⇒r=26m
i) Area of path=π(R
2
−r
2
)
=
7
22
((26+4)
2
−(26)
2
)
=
7
22
×224
=704m
2
ii) Cost of graveling
= (704×1.50)
= Rs.1056
iii) Area of plot=πr
2
=
7
22
×26×26
=2124.57m
2
∴ Cost of turfing at the rate of 45 paise per m
2
m2
=Rs.(2124.57×0.45)
=Rs. 956•06