Question

A square has a diagonal of 18 cm. Find the perimeter of the square​

Answer 1

Answer:

the diagonal of the square is 18 cm.

by Pythagoras theorem,

(hypotenuse)^2= (base)^2+ (height)^2

18^2=x^2+x^2

324=2x^2

x^2=324/2

x^2=167

x=√167

Perimeter=4×side

=4×√167

Answer 2

Answer:

Perimeter of the square is 50.8 cm.

solution:-

we know that the diagonal of the square bisect each other at 90° .

so , 4 right angle triangle is formed inside

we have got the perpendicular as 9 cm and base 9 cm.

using Pythagoras theorem we can find hypotenuse

h^2=(9)^2+(9)^2

h^2= 162

h=√162

hypotenuse is 12.7 cm .

side of the square is 12.7 cm

perimeter will be = 4(12.7)

50.8 cm

Step-by-step explanation:

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