Question

A square has a side of length x - 6 . A rectangle has a length of x+6 and a width of x - 6. What is the total area of the square and the rectangle ?

A  x-12

B  2x^2 +12x

C  2x^2 - 12x

D  None of these

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Answer 1

Answer:

area of square = x²+6²-12x area if rectangle= x²+6x-6x-36

Step-by-step explanation:

area of square = side*side

= x-6(x-6)

= x²+6²-12x

area of rectangle = length*breadth

= (x+6)(x-6)

= x²+6x-6x-36

Answer 2

Answer:

(c) 2x^2-12x

Step-by-step explanation:

Side of square = (x-6)

Area of square = (x-6)^2 {:. (a-b)^2 = a^2-2ab+b^2}

= x^2-12x+36

L of rect. = x+6

W of rect. = x-6

Area = (x+6)(x-6). {:.(a+b)(a-b) = a^2-b^2}

= x^2-36

Total of area of sq. And rect. = x^2q-12+36+x^2-36=2x^2-12x