Question

a square has diagonal 3√2 cm.find it's area.​

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Given,

Length of the diagonal of the square = $3\sqrt{2}$

Area of the square = ?

w.k.t,

Diagonal of a square = $\sqrt{2}$ * area

=> d = $\sqrt{2}$ * a

Substitute the given data.

=> d = $\sqrt{2}$ * a

   $3\sqrt{2}$ = $\sqrt{2}$ * a

   $3\sqrt{2}$ /$\sqrt{2}$ = a

   3 = a

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