Question

A square hole of cross sectional area 4cm2 is drilled across a cube with its length parallel to a side of a cube. if an edge of the cube measures 5 cm, what is the total surface area (in cm2) of the body so formed?

Answer 1

163cm² is the answer to your question

Answer 2

Answer:

Total surface area of the body formed is 182 cm sq.

Step-by-step explanation:

Given : A square hole of cross sectional area 4 cm sq. is drilled across a cube with its length parallel to a side of a cube. If an edge of the cube measures 5 cm.

To find : What is the total surface area (in cm sq.) of the body so formed?

Solution :

Edge of the cube is a=5 cm.

Area of the cube is $A_c=6a^2$

$A_c=6(5)^2=6\times 25=150cm^2$

Area of cross sectional is A=4 cm sq.

Total surface area of the cube have a hole of cross-sectional area is

$TSA=A_c-2(A)$

$TSA=150-2(4)$

$TSA=150-8$

$TSA=142 cm^2$

Area of the four walls of the hole made parallel to the side of the cube is

$4\times 5\times 2=40cm^2$

Total surface area of the body formed is 142+40=182 cm sq.