A square is inscribed in a circle of diameter D and another square is circumscribing the circle . Find the ratio of the area of the outer square to the area of the inner square
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inner square:
acc to phythag
2*side^2=D^2
side^2=D^2/2
outer circle
as D=side
area=D^2
ratio=2:1 proved
acc to phythag
2*side^2=D^2
side^2=D^2/2
outer circle
as D=side
area=D^2
ratio=2:1 proved
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