a square is inscribed in a circle of diameter d and another square is circumscribing the same circle.find the ratio of the outer square to the area of the inner square.
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in the qustion the side of the outer sq will be = d
and the innner sq side let be x
so now by pythagorous -
x sq +x sq=d sq
2x sq= d sq
= x= d/2root
=so now the ratio is d sq/ d/root 2sq
= 2:1
and the innner sq side let be x
so now by pythagorous -
x sq +x sq=d sq
2x sq= d sq
= x= d/2root
=so now the ratio is d sq/ d/root 2sq
= 2:1
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