Question

A square is put together by two triangles. The hypotenuse is 11 cm and width of 8 cm. Find the height of the triangle (this is related to Pythagoras theorem)

Answer 1

by Pythagoras theorem ,

h^2 = p^2 + b^2

11^2 = p^2 + 8^2

p^2 = 121 - 64 = 57

p =√57 = 7.54cm.

Answer 2

By Pythagoras theorem :

$(Perpendicular)^2+(Base)^2=(Hypotenuse)^2\\\\(8)^2+(Base)^2=(11)^2\\\\(Base)^2=121-64\\\\Base=\sqrt{57}$

$Base =7.54cm$