A square lawn is surrounded by a path 2.5m wide.If the area of the path is 165m2,find the area of the lawn.
Answers
Answered by
57
Hey there!
Your Dearest Moderator is here to help! ♡♥
_________________________________________
Given, Width of path = 2.5 m
Area of path = 165 m²
Let the Side of Lawn be " a " .
Area of Lawn = a²
Now, If we consider that path is also a part of a new square then the side of lawn + path = a + 2(2.5) = a+5 .
It's Area = (a+5)²
From the situation,
We can say that,
Area of path =( Area of Lawn + Path) - ( Area of Lawn)
165 = (a+5)² - a²
165 = 25 + 10a
140 = 10a
a = 14m .
Therefore ,Side of Lawn = 14m.
Area of Lawn = 14² = 196m²
___________________________________________
Hope you are helped ❣
#Enjoy using Brainly.in ❀
Your Dearest Moderator is here to help! ♡♥
_________________________________________
Given, Width of path = 2.5 m
Area of path = 165 m²
Let the Side of Lawn be " a " .
Area of Lawn = a²
Now, If we consider that path is also a part of a new square then the side of lawn + path = a + 2(2.5) = a+5 .
It's Area = (a+5)²
From the situation,
We can say that,
Area of path =( Area of Lawn + Path) - ( Area of Lawn)
165 = (a+5)² - a²
165 = 25 + 10a
140 = 10a
a = 14m .
Therefore ,Side of Lawn = 14m.
Area of Lawn = 14² = 196m²
___________________________________________
Hope you are helped ❣
#Enjoy using Brainly.in ❀
prince526:
sonu Kumar Delhi and the
Answered by
52
heya mate ,,,, think here is your answer
Given ,
Area of the path = 165m^2
width of the path = 2.5m
now let
one side of the inner square to be a
then the side of the outer square is a + 2w
area of inner square = a^2
area of outer square
= (a + 2w ) ^2
= ( a^2 + (2w ^2 ) + 2 × a × 2w )
= a^2 + 4w^2 + 2 × a × 2w
area of path = area of outer square - area of inner square
= a^2 + 4w^2 + 4aw - a^2 = 165
= 4w^2 + 4aw = 165
by substituting the value of w in the equation we get
25 + 10a = 165
a = 14
so now
area of lawn = a^2 = 14 ^2 = 196m^2
Given ,
Area of the path = 165m^2
width of the path = 2.5m
now let
one side of the inner square to be a
then the side of the outer square is a + 2w
area of inner square = a^2
area of outer square
= (a + 2w ) ^2
= ( a^2 + (2w ^2 ) + 2 × a × 2w )
= a^2 + 4w^2 + 2 × a × 2w
area of path = area of outer square - area of inner square
= a^2 + 4w^2 + 4aw - a^2 = 165
= 4w^2 + 4aw = 165
by substituting the value of w in the equation we get
25 + 10a = 165
a = 14
so now
area of lawn = a^2 = 14 ^2 = 196m^2
Similar questions