Question

A square loop of sides 5 cm carrying a current of 0·2 A in the

clockwise direction is placed at a distance of 10 cm from an

infinitely long wire carrying a current of 1 A as shown. Calculate

(i) the resultant magnetic force, and (ii) the torque, if any, acting

on the loop.​

Answer 1

Explanation:

.. I hope it will help ful for you....

Answer 2

The answer are as follows;

The answer are as follows; (i) 7 × 10⁻⁹ N

The answer are as follows; (i) 7 × 10⁻⁹ N (ii) 0

GIVEN

A square loop of sides 5 cm carrying a current of 0·2 Am in the clockwise direction is placed at a distance of 10 cm from an infinitely long wire carrying a current of 1 A.

TO FIND

(i) the resultant magnetic force, and (ii) the torque, if any, acting on the loop.

SOLUTION

The above problem can be simply solved as follows:

(I)

Force on AB = Fᵃᵇ = (μ₀I₁I₂/2πr)L

= (2 × 10⁻⁷ × 1 × 0.2 × 5 × 10⁻²)× 10 × 10⁻²

= 2 × 10⁻⁸N (Attractive).

Force acting on CD =

Fᶜᵈ = (2 × 10⁻⁷ × 1 × 0.2 × 5 × 10⁻²)/15 × 10⁻²

= 1.3 × 10⁻⁸ N (Repulsive.)

Fⁿᵉᵗ = Fᵃᵇ - Fᶜᵈ

= 7 × 10⁻⁹ N

(ii) Since, Both the forces are collinear, do not produce any torque.

Therefore,

Torque = 0

Hence, The answer are as follows;

Hence, The answer are as follows; (i) 7 × 10⁻⁹ N

Hence, The answer are as follows; (i) 7 × 10⁻⁹ N (ii) 0

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