Question

a square loop of wire side length 10 cm is placed at and angle of 45 degree with a magnetic field that changes uniformly from 0.17 to zero in 0.7 sec the induced current in the loop is?

Answer 1

Answer:

The answer will be 1.71 mA

Explanation:

According to the problem the length of one side of the square is 10 cm

and the angle which is made by the loop with the magnetic field is 45 degree.

Now we know that magnetic flux, Ø = b.a.cosθ [ where a is the area]

 Therefore E = d/dt (b.a.cosθ) = a xcosθ x db/dt

Now as given the magnetic field changes from 0.17 to zero and we know that

Now induced emf = dØ/dt

Therefore E = (0.1) x(0.1) x 1/√2 x 0.17/0.7 = 1.71 x 10^(-3)

Therefore the induced current , I = E/r = 1.71 x 10^(-3)/1 = 1.71 mA(approx)