A square loop of wire with 10 turns and a side length of 1 m is placed in a changing magnetic field. If the magnetic field changes from 2 T to 4 T within 8 seconds, what is the average induced emf?
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Answer:
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Explanation:
L=10cm=10
−2
m ,θ=45
Initial magnetic field B
i
=0.1T
Final magnetic field B
f
=0T
Δt=0.7s ,R=1Ω
Now ϕ
B
=BAcosθ=
2
10
−3
wB
ϕ
B
f
=0wb
ε=
Δt
∣Δϕ
B
∣
=
2
10
−3
×
0.7
1
=1mV
I=
R
ε
=
1Ω
1mV
=1mA
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