Question

a square minus b square by c square equals to ​

Answer 1

Answer:

a²-b²-c²+2bc = (a+b-c)(a-b-c)

Explanation:

a²-b²-c²+2bc

= a²-(b²+c²-2bc) /* Take "-" common in last three terms */

= a² - (b-c)²

/* We know the ,

algebraic identity :

x²+y²-2xy = (x-y)² */

= [a+(b-c)][a-(b+c)]

/* By algebraic identity :

x²-y² = (x+y)(x-y) */

= (a+b-c)(a-b-c)

Therefore,

a²-b²-c²+2bc =(a+b-c)(a-b-c)