Question

A+square+minus+b+square+minus+2b+minus+1

Answer 1

We have,

$\quad {a}^{2} - {b}^{2} - 2b - 1 \\ \\ = {a}^{2} - ( {b}^{2} + 2b + 1) \\ \\ = {a}^{2} - \left( {(b)}^{2} + 2(b)(1) + {(1)}^{2} \right) \\ \\ = {(a)}^{2} - {(b + 1)}^{2} \\ \\ = (a - b - 1)(a + b + 1)$