a square minus b square minus C square plus 2bc
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Answered by
51
a²-b²-c²+2bc
a²-(b²+c²-2bc)
a²-(b-c)²
(a+b-c)(a-b+c)
a²-(b²+c²-2bc)
a²-(b-c)²
(a+b-c)(a-b+c)
Rohitdadel:
how did you did it can send me pic of this solving step by step
plz
Answered by
11
Answer:
a²-b²-c²+2bc = (a+b-c)(a-b-c)
Explanation:
a²-b²-c²+2bc
= a²-(b²+c²-2bc) /* Take "-" common in last three terms */
= a² - (b-c)²
/* We know the ,
algebraic identity :
x²+y²-2xy = (x-y)² */
= [a+(b-c)][a-(b+c)]
/* By algebraic identity :
x²-y² = (x+y)(x-y) */
= (a+b-c)(a-b-c)
Therefore,
a²-b²-c²+2bc =(a+b-c)(a-b-c)
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