a square of a natural number subtracted from its cube is 48.find the number.PLEASE SHOW FULL PROCESS
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let the number be x
x^3-x^2 = 48
x^2(x-1)=16(3) = 16(4-1) = 4^2(4-1)
so from this, we can say that x=4
x^3-x^2 = 48
x^2(x-1)=16(3) = 16(4-1) = 4^2(4-1)
so from this, we can say that x=4
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