Question

A square of area 49 sq. cm is cut out from a rectangle of length 9 cm. It is the largest square that can be cut out from this rectangle.



What will be the area of the remaining part?

Answer 1

let breadth of rectangle be x

since it was the largest square can be cut....

area of rectangle must be greater than 49(7²)

=> 7² < length × breadth < 8²

=> 49 < 9x < 64

numbers between 49 and 64 that are divisible by 9 are 54,63

=> area of remaining part is

54 - 49 (or) 63 - 49

=> 5sq.cm (or) 14sq.cm

Answer 2

Answer:

14cm^2

Step-by-step explanation:

ar s=49cm^2

side=7,7

given= lenght=9

if the square is the maximum that can be cut out then we get 7 as the breadth becoz the the side of the square is 7

so the l=9cm,b=7cm

the are of the rectangle =7*9=63

therefore the remaining area= 63-49=32

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