a square of diagonal 8 cm result inscribed in a circle . find the area of the region like outside the circle and inside the square
Answers
Answered by
5
Dear please check the pic of square circumscribed in a circle. You should have written "Circumscribed" instead of inscribed.
Solution:
Since the square is inscribed in a circle. Therefore, it is property of circumscribed square in a circle that it's diagonal is the diameter of the circle.
Therefore, area of region = (π/4) x diameter^2
= (π/4) x 8^2
=50.265 cm^2
Area of square = (Diagonal^2)/2
= (8^2)/2 = 32 cm^2
Hence the area of the required region = 50.265 - 32
= 18.265 cm^2
Solution:
Since the square is inscribed in a circle. Therefore, it is property of circumscribed square in a circle that it's diagonal is the diameter of the circle.
Therefore, area of region = (π/4) x diameter^2
= (π/4) x 8^2
=50.265 cm^2
Area of square = (Diagonal^2)/2
= (8^2)/2 = 32 cm^2
Hence the area of the required region = 50.265 - 32
= 18.265 cm^2
Attachments:
adi2233:
Answer is 16 5 - 32 CM
Answered by
1
A square of Diagonal 8 cm is inscribed in a circle.
From the above statement it is clear that radius of the circle is 4 cm.
Area of the circle = pie x r^2 = 3.14 x 4^2
= 3.14x16 = 50.24 cm^2
Area of the Square = (1/2) X Diagonal^2
= (1/2) X 8^2 = (1/2) X 64 = 32 cm^2
Area of the space outside square = 50.24 - 32 = 18.24 cm^2
From the above statement it is clear that radius of the circle is 4 cm.
Area of the circle = pie x r^2 = 3.14 x 4^2
= 3.14x16 = 50.24 cm^2
Area of the Square = (1/2) X Diagonal^2
= (1/2) X 8^2 = (1/2) X 64 = 32 cm^2
Area of the space outside square = 50.24 - 32 = 18.24 cm^2
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