A square of length 3cm is located distance of 25 cm from concave mirror of focal length 10 cm . The centre of square is at the axis of mirror .What is the area enclosed by image of the square.
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1/f =1/u + 1/v
1/v = 1/-10 - 1/-25
= -3/50
v = -50/3
m h'/h =-v/u
h is the height of the object
h'/3 = -(50/3)/-25 h = -2cm
=(-2cm)^2
= 4cm^2 so the area enclosed by image of wire.
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