Question

a square of side 1 cm is placed perpendicular to the principal axis of a concave mirror of focal length 10cm the distance of 20cm the area enclosed by the image of the wire is​

Answer 1

E

Solution :

Given focal length of concave mirror f=−15cm u=−20 cm Magnification m=fu−f                                 =−15−20+15                                 m=3cm The area enclosed by the image of the wire =m2 =9 cm

Answer 2

Answer:

The area enclosed by the wire is 9 cm