Question

a square of side 2cm is joined with a rectangle of length 15cm and breadth 10cm.find perimeter of combined shape

Answer 1

perimeter of rectangle -2= 2(l+b) -2
2(25)-2
48cm
perimeter of square -2= 4(2)-2
6cm
now adding both
48+6= 54cm

Answer 2

The perimeter of combined shape is 54 cm

Solution:

Given that,

Square of side 2 cm is joined with a rectangle of length 15 cm and breadth 10 cm

We have to find the perimeter of combined shape

Perimeter of square = 4(side length) - side length of one side which is in touch with one side of rectangle

Therefore,

Perimeter of square = 4(2) - 2 = 8 - 2

Perimeter of square = 6 cm

Perimeter of rectangle = 2(length + breadth) - 2

Perimeter of rectangle = 2(15 + 10) - 2

Perimeter of rectangle = 50 - 2

Perimeter of rectangle = 48 cm

Thus the perimeter of combined shape  is:

perimeter of combined shape  = 6 + 48 = 54

Thus the perimeter of combined shape is 54 cm

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