Question

A square of side 4 cm is inscribed in a circle.Find the area enclosed between the circle and the square.(use= 22/7)

Answer 1

The diagonal of the square equals the diameter of the circle

By Pythagoras theorem Diagonal = √(4² + 4²) = 5.657 cm
Radius = 5.657 / 2 = 2.828 cm

Area between circle and square = Area of circle - area of square
                                                         = 22/7 x 2.828² - 4²
                                                         = 9.143 cm²

Answer 2

Side of square =4cm

Diagonal of square √16+16

4√2cm

Diagonal of square is equal to diameter of circle 4√2cm

So raidus of circle 2√2 cm

Area of square 4×4=16cm2

Area of circle =MR2

22/7 ×2√2 ×2√2 = 25.14 cm2 ..

Area of enclosed between the circle n square =25.14 -16= 9.14cm2