a square of side 4cm. is inscribed in a circle. Find the area between them?
sumak:
reply fast pls
Answers
Answered by
3
Required area = Area of the circle -Area of the square
Diagonal of the square = Diameter of the circle
⇒Radius of the circle= (√2s)/2
⇒r=2✓2 cm
Therefore, required area = (22/7)(8)-16
=(176/7)-16
=25.14-16
=9.14 cm²
Diagonal of the square = Diameter of the circle
⇒Radius of the circle= (√2s)/2
⇒r=2✓2 cm
Therefore, required area = (22/7)(8)-16
=(176/7)-16
=25.14-16
=9.14 cm²
can i know that how was the no. 8 came
2✓2 whole square is 8
okay
but how the radius was found
by pythagoras ?
Yes
Similar questions
English,
8 months ago
Math,
8 months ago
Physics,
1 year ago
Political Science,
1 year ago
English,
1 year ago