a square of side 4cm is inscribed in a circle. find the area enclosed between the circle and the square
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Answer:
9.143 cm²
Step-by-step explanation:
The diagonal of the square equals the diameter of the circle
By Pythagoras theorem Diagonal = √(4² + 4²) = 5.657 cm
Radius = 5.657 / 2 = 2.828 cm
Area between circle and square = Area of circle - area of square
= 22/7 x 2.828² - 4²
= 9.143 cm²
HOPE IT HELPS!!!
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