Question

a square of side 7cm exclosses a circle touching all the four sides, then the area enclosed between the square and the circle is _________cm²​

Answer 1

Answer:

Area of the square =7*7=49 sq cm

Area of the circle = 22/7*7=22 sq cm

Area between the square and circle is (49-22)=27sq cm.

Answer 2

Answer:

10.5cm²

Step-by-step explanation:

Given :

A square of side 7 cm enclosed a circle touching all its four sides.

Side of the square = 7cm.

To be found :

The area enclosed between the square and the circle.

→Follow the attached image

Now,

To find area enclosed between the square and the circle, we have to find- area of circle and area of square.

Then, we have to subtract area of circle from the area of square.

So,

Area of square = (side)×(side) = (side)² unit sq.

Area of square = (7)² = 49 cm²

As from the given statement of question, we can get the diameter of the circle.

The diameter of the circle = side of the square

So, diameter = 7cm

Radius(r) of the circle = (7/2) cm

∴ 2r = diameter or diameter = (r/2)

Now,

Area of circle = πr² unit sq.

\begin{gathered}\tt Area \: of \:the\: circle = \frac{ {\cancel{22}}^{11} }{\cancel{7} }\times\frac{\cancel{7}}{\cancel{2}} \times \frac{7}{2} \\ \\ \tt Area\: of\:the\:circle = \frac{77}{2} = 38.5 \:cm^{2}\end{gathered}Areaofthecircle=72211×27×27Areaofthecircle=277=38.5cm2

Now,

area enclosed between the square and the circle

= Area of square - Area of circle

= 49 - 38.5

= 10.5 cm²

Hence,

The area enclosed between the square and the circle is \red{\underline{\underline{\tt{10.5 cm^{2} }}} }10.5cm2 .

Hope it helps you!