Question

a square of side 9 CM has the same perimeter as a rectangle with length 11 cm find the breadth and area of the rectangle ​

Answer 1

Answer:

hope it helps you

Step-by-step explanation:

side of a square=9cm

perimeter of a square=4×side

=4×9cm

=36cm

A.T.Q, perimeter of a square=perimeter of a rectangle

length of a rectangle=11cm

perimeter of a rectangle =2(length+breadth)

therefore, breadth of a rectangle=p/2- length

=36cm/2-11cm

=18cm-11cm

=7cm

area of a rectangle=length×breadth

=11cm×7cm

77cm²

Answer 2

$\large \underline{\underline{ \sf{given :}}}$

$\blue{ \sf{side \: of \: square \: = 9 \: cm}} \\ \blue{ \sf{length \: of \: rectangle = 11 \: cm}}$

$\large \underline{\underline{ \sf{to \: find :}}}$

$\green{ \sf{breadth \: of \: rectangle }} \\ \green{ \sf{area \: of \: rectangle }}$

$\large \underline{\underline{ \sf{formulae :}}}$

$\pink{ \sf{perimeter \: of \: square = 4(side)}} \\ \pink{ \sf{perimeter\: of \: rectangle =2( l + b)}} \\ \pink{ \sf{area \: of \: rectangke = l \times b}}$

$\large \underline{\underline{ \sf{solution:}}}$

$\red{ \sf{perimeter \: of \: square = perimeter \: of \: rectangle}} \\ \red{ \sf{4(side) =2( l + b)}} \\ \red{ \sf{4(9) = 2(11 + b)}} \\ \red{ \sf{36 = 22 + 2b}} \\ \red{ \sf{2b = 36 - 22}} \\ \red{ \sf{2b = 14}} \\ \red{ \sf{b = \frac{14}{2} }} \\ \boxed{ \red{ \sf{b = 7 cm}}}$

$\blue{ \sf{area \: of \: rectangle = l \times b}} \\ \blue{ \sf{area \: of \: rectangle = 7 \times 11}} \\ \boxed{ \blue{ \sf{area \: of \: rectangle = 77 \: cm {}^{2} }}}$