A square park has its side 32m. At each corner of the park there is a flower bed in the form of a quadrant of radius 10m. Find the area of the remaining part of the park.
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Answered by
44
Heya...
Here is your answer ---
=> Side of park = 32 m
=> Area = Side × Side = Side ^2
=> Area of park = 32^2 = 1024 m^2
=> Area of 4 quadrants (flower bed) = Area of full circle
=> Area of 4 flower beds (circle) = π × r^2
= 22/7 × 10^2
= 22/7 × 100
= 2200 / 7
= 314.28 m^2
=> Area of remaining part = Area of park - Area of 4 flower beds
= 1024 - 314.28
= 709.72 m^2
HOPE IT HELPS....!!!
Here is your answer ---
=> Side of park = 32 m
=> Area = Side × Side = Side ^2
=> Area of park = 32^2 = 1024 m^2
=> Area of 4 quadrants (flower bed) = Area of full circle
=> Area of 4 flower beds (circle) = π × r^2
= 22/7 × 10^2
= 22/7 × 100
= 2200 / 7
= 314.28 m^2
=> Area of remaining part = Area of park - Area of 4 flower beds
= 1024 - 314.28
= 709.72 m^2
HOPE IT HELPS....!!!
Uejsks:
You directly written area of 4 quadrant and you have find just area of one quadrant
And thanks for the answer
Answered by
6
Answer:
Step-by-step explanation:
Side of Square park=32m
Area of square park=S×S
=(32×32)sq. m
=1024sq. m
As we know,
Area of 4 quadrants = Area of a whole circle = πr^2
Area of four quadrants=3.14×10m^2
=3.14×100m
=314m
Area of remaining part=Area of square-Area of four quadrant
=1024m^2-314m
=710m^2 ans.
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