Question

a square park is of side 32m .At each corner of the park, there is a flower bed in the form of a quadrant of radius 10m. find area of the remaining part of the park.[take \pi 3.14]

Answer 1

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Here is your answer.
Side of Square is 32 m
Area of Square = 32 × 32
= 1024 sq.m

At each corner there is a quadrant Park
so four quadrant equal one circle
Radius is 10 m

Area of circle = πr^2
$= 3.14 \times (10) {}^{2} \\ = 3.14 \times 100 \\ = 314 \: m {}^{2}$

Therefore the Area of remaining Park is
$= 1024 - 314 \\ = 710m {}^{2}$

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Answer 2

Here is your answer.

Side of Square is 32 m

Area of Square = 32 × 32

= 1024 sq.m

At each corner there is a quadrant Park

so four quadrant equal one circle

Radius is 10 m

Area of circle = πr^2

\begin{gathered} = 3.14 \times (10) {}^{2} \\ = 3.14 \times 100 \\ = 314 \: m {}^{2} \end{gathered}

=3.14×(10)

=3.14×100

=314m

Therefore the Area of remaining Park is

\begin{gathered} = 1024 - 314 \\ = 710m {}^{2} \end{gathered}

=1024−314

Hence, the answer is 710m

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