Question

A square park is of side 50 m. A path of width 2.5 m runs around the garden inside it. Find the area of
the path.​​

Answer 1

Answer:

Let ABCD, the square garden of side= 30 m.

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 m

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malso

Let ABCD, the square garden of side= 30 m.PQRS is the region inside the garden.so,PQ = (30 -1-1 ) = 28 malsoPS = ( 30 – 1 – 1 ) = 28 m

(i) Area of the path = Area of ABCD – Area of PQRS

(i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]

(i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784

(i) Area of the path = Area of ABCD – Area of PQRS = [( 30 x 30) – (28 x 28)]= 900 – 784 = 116 sq.m

(ii) Area of the remaining portion in which the grass is planted = Area of square PQRS

(ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28

(ii) Area of the remaining portion in which the grass is planted = Area of square PQRS = 28 x 28 = 784 sq.m

cost of planting the grass in the region PQRS = area x cost = 764 x 40

cost of planting the grass in the region PQRS = area x cost = 764 x 40 =31,360