A square piece of cardboard is to be used to form a box without a top by cutting off squares, 3 cm on a side from each corner and then folding up the sides. The volume of the box must be 3000cm^3
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Step-by-step explanation:
Let the length of the each side of the square which is cut from each corner of the tin sheet be x cm.
By folding up the flaps, a cuboidal box is formed whose length, breadth and height are 18−2x,18−2x and x respectively.
Then, its volume V is given by
V=(18−2x)(18−2x)x
⇒
dx
dV
=324−144x+12x
2
and
dx
2
d
2
V
=−144+24x
The critical numbers of V are given by
dx
dV
=0
⇒324−144x+12x
2
=0
⇒x
2
−12x+27=0
⇒x=3,9.
But, x=9 is not possible. Therefore, x=3.
Clearly, (
dx
2
d
2
V
)
x=3
=−144+72=−72<0.
So, V is maximum when x=3 i.e., the length of each side of the square to
be cut is 3cm.
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