a square piece of paper of side 12cm is rolled to form of a cylinder . find the curved surface of area of the cylinder
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10
Side =12 cm
So 2 pie r = 12 cm
2 pie r =12
Pie r = 6 cm
r= 6 ×7÷22
r = 21/11
CSA of cylinder = 2 pie rh
2 pie rh =2×22/7 ×21/11×12
= 144 cm ^2
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Answered by
7
Circumference of the base circle = 2 x pi x r =12cm
Height of the cylinder = 12 cm
C.S.A of a cylinder = 2 x pi x r x h
= (2 x pi x r) x h
=12 x 12
= 144 sq cm.
Height of the cylinder = 12 cm
C.S.A of a cylinder = 2 x pi x r x h
= (2 x pi x r) x h
=12 x 12
= 144 sq cm.
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