A square plate is contracting at the rate of 4cm/sec find the rate of decreases of perimeter when the side of the square 8 is 14 cm.
Answers
Answered by
1
Step-by-step explanation:
Given:Let x be the side of the square plate and A be the area of the square plate
Given:
dt
dA
=−2 and x=16cm
A=x
2
⇒
dt
dA
=2x
dt
dx
⇒−2=2x
dt
dx
⇒
dt
dx
=
x
−1
=
16
−1
Let P be the perimeter then P=4x
dt
dP
=4
dt
dx
=4×
16
−1
=−0.22
∴ the perimeter of the square plate decreasing ar the rate of
4
1
1/4 cm/ sec
Similar questions