A square plate of side 20 m is placed horizontally 2m below the surface of water. The atmospheric pressure is 100000 Pa. Calculate the total thrust on the plate
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Answer:
Square side of plate (s) = 20 m
Depth below water (d) = 2m
Atmospheric Pressure (atm) = 100000Pa
Density of water (p) = 1000 kg/m³
Acceleration due to gravity (g) = 9.8 m/s²
Total Pressure = atm+dpg
= 100000+(2*1000*9.8) Pa
= 100000+19600 Pa
= 119600 Pa
Area of the square plate = s²
= (20)² m²
= 400 m²
Pressure = Thrust/Area
= 119600 = Thrust/400
= 47840000 N is the Thrust.
I hope this helps.
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