Question

a square plus b square is equal to ?

Answer 1

To find $A^{2}+B^{2}=?$

To find the given we have to apply algebra identities which is derived from the standard binomial theorem  

$(a+b)^{2}=a^{2}+2 a b+b^{2} \rightarrow(1)$

$(a-b)^{2}=a^{2}-2 a b+b^{2} \rightarrow(2)$

Let a = A and b = B from the given  

Substituting a = A and b = B in the (1) identity

$(a+b)^{2}=a^{2}+2 a b+b^{2}$

$(A+B)^{2}=A^{2}+2 A B+B^{2}$

$(A+B)^{2}-2 A B=A^{2}+B^{2} \rightarrow(3)$

Substituting a = A and b = B in the (2) identity

$(a-b)^{2}=a^{2}-2 a b+b^{2}$

$(A-B)^{2}=A^{2}-2 A B+B^{2}$

$(A-B)^{2}+2 A B=A^{2}+B^{2} \rightarrow(4)$

Thus, we obtained two values for the given which is $\bold{(A+B)^{2}-2 A B=A^{2}+B^{2}\ and\ (A-B)^{2}+2 A B=A^{2}+B^{2}}$. They are two results for the given sum because it is suitable for the two identities in the expression of algebra.

Answer 2

here's you're answer

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