a square portion of diagonal equal to radius is removed from uniform circulsr plate of radius R as shown in figure then shift in center of mass is, xshift=R/2(2pie-1)
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Explanation:
A sqaure sheet with diagonal r and mass m is cut off from it. Assuming centre of mass of circle to be origin i.e. at 0. Centre of mass of square sheet will be at distance of r/2 from it. Hence, centre of mass of remaining part lies at a distance r/2(2π-1) towards right from centre of the circle
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